Taking a panoramic photo of massive or large-scale objects is often a lot more challenging than expected because even if you have a camera with this setting option, without a steady hand and a professional eyes, the results can be lackluster. Making several shots and stitching them together into the panorama would be a solution.
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- Teorex PhotoStitcher Verdict If you have a recent version of Photoshop, you can acheive the same results and won't need any further software. Of course, if you haven't you might find it quite useful.
PhotoStitcher is a powerful, efficient, and easy-to-use photo stitching software that lets you combine overlapping photos to produce stunning panoramic pictures in just a couple of clicks, whether 1D (horizontal OR vertical) or 2D (horizontal AND vertical). Automated stitching process makes it easy to create breathtaking landscapes – you don’t have to be a professional photographer or know how to use professional photograph editing software – in fact you don’t have to be tech savvy at all! And if you get unsightly empty areas on the final stitched image, you can use Inpaint (shareware, get free here) to momentarily restore those black areas from the surrounding parts of the photo, saving the natural non-cropped look of the photo and retaining author’s composition.
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Image set p=x^2+1 (-2<=x<=2)?
Photostitcher 2 1 2 X 2/3
2 Answers
Explanation:
Adding #1, 1 le x^2+1 le 5# .
Image Set.
Hence, the right option is #C [1,5]# .
Explanation:
.
Photostitcher 2 1 2 X 24
The image of a function is all the possible values a function can have in a specified domain.
Your specified domain is #-2 < x < 2# . We have to check and see what values #p(x)# can have between #-2# and #2# .
This is a quadratic function, i.e. it is a parabola. Since the coefficient of #x^2# is positive, the parabola opens upward. This means that the vertex of the parabola is where the function has its minimum value.
If the function of your parabola is given in the form of: Smartdown 1 0 4 download free.
In this problem, #a=1# and #b=0# because there is no #x# term.
![Photostitcher Photostitcher](https://insmac.org/uploads/posts/2019-08/1565709259_photostitcher_03.jpg)
Now, we can plug this value into the function to find the #y# -coordinate of the vertex:
This means that at #x=0# the value of your function is #1# and this is the minimum value of your function between #-2# and #2# as we can see from the graph below:
graph{x^2+1 [-10, 10, -5, 5]}
But the maximum value of your function would be #oo# if your domain were not restricted. Since your domain is given as:
let's find the value of your function at #-2# and #2# :
So, the maximum value of the function in this domain is #5# and the minimum value is #1# which is why option #C# is correct.